Chess Training

Here is yet another excellent example of corresponding squares from Dvortesky's Endgame Manual and the process one must use to figure them out. f4(w) and f6(b) are in obvious correspondence, for if 1...Kg6 2.e7 Kf7 3.Kxf5 Kxe7 4.Kg6 wins. When White's king is on h4, Black's king must be on g6, and not f6, because of Kh5. So h4(w) and g6(b) correspond. Using these pairs or corresponding squares, we can surmise a third pair by the adjoining squares principle: White: f4 and h4 adjoin g3 Black: f6 and g6 adjoin g7 Therefore, g3(w) and g7(b) correspond. Let's examine f3: f3 Adjoins f4 and g3, whose corresponding squares are f6 and g7. f6 and g7 adjoin to g6, therefore f3(w) and g6(b) correspond. Let's examine h3: h3 adjoins h4(g6 corresponds) and g3(g7 corresponds), and it's corresponding square is f6, which adjoins g6 and g7. Therefore, h3(w) and f6(b) correspond. So far each square we have examined has a single corresponding square for black. Let's go fur...